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![]() This is a workaround until we have a better heuristic (maybe shortest path?) to choose between multiple paths in the graph. Since the (abstract) graph has no idea about memory translations, getPath() may even yield paths that are no valid translation because a pair of inbound/outbound edges must not neccessarily share a common address window, but from the perspective of the abstract graph present a valid path. The callback function is used by the MemoryManager to verify if a path candidate represents a valid translation. |
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